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solve sqrt(x+2) ge x...

solve `sqrt(x+2) ge x `

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The correct Answer is:
` x in [-2,2]`
`sqrt(x+2) ge x `
`rArr x+2 ge x^2 for x ge 0 `
`rArr x^2 - x-2 le 0 `
`rArr ( x-2)( x+1)le 0 `
`rArr in [0,2]`
`x lt "0 always valid but" x + 2 ge 0 `
`rArr x ge -2`
`x in [ -2 , 2]`
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