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Prove that in two concentric circles, th...

Prove that in two concentric circles, the chord of the larger circle, which touches the smaller circle, is bisected at the point of contact.

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To prove that in two concentric circles, the chord of the larger circle, which touches the smaller circle, is bisected at the point of contact, we can follow these steps: ### Step-by-Step Solution: 1. **Define the Circles and Points**: Let O be the common center of two concentric circles C1 (the smaller circle) and C2 (the larger circle). Let AB be a chord of circle C2 that touches circle C1 at point P. **Hint**: Identify the center and the points involved in the problem clearly. ...
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Knowledge Check

  • In two Concentric circles, AB and CD are two chords of the outer circle which touch the inner circle at E and F. Then :

    A
    AB = CD
    B
    `AB = (1)/(2) CD`
    C
    `AB ne CD`
    D
    None of these
  • If two concentric circles are of radii 5 cm and 3 cm, then the length of the chord of the larger circle which touches the smaller circle is

    A
    6 cm
    B
    7 cm
    C
    10 cm
    D
    8 cm
  • Let two chords AB and AC of the larger circle touch the smaller circle having same centre at X and Y. Then XY = ?

    A
    `BC`
    B
    `1/2 BC`
    C
    `1/3 BC`
    D
    `1/4 BC`
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