" 0) "6u^(2)+17u+12

Calculate the the binding energy per nucleon for a _6C^(12) nucleus. Nuclear mass of _6C^(12) = 12.000000 a.m.u.,mass of hydrogen nucleus =1.007825 a.m.u. and mass of neutron = 1.008665 a.m.u.

If u_(0) = 8 , u_(1) = 3 , u_(2) = 12 , u_(3) = 51 , then the value of Delta^(3) u_(0) is

The binding energy of ._(17)^(35 )Cl nncleus. Take atomic mass of ._6^(12) C as 12.000 an u Take R_(0) =1.2 xx 10-^(15) m .

Let f be a composite function.of x defined by f(u)=(1)/(u^(3)-6u^(2)+11u-6) where u(x)=(1)/(x) .Then the number of points x where f is discontinuous is

Calculate the binding energy for nucleon of . _6^(12) C nucleus, if mass of proton m_p = 10078 u , mass of neutron m_n = 1.0087 u , mass of C_12, m_C =12.0000 u , and 1 u =931 .4 MeV .

If "n"epsilonN" and "u_(1)=x^(n),u_(2)=x^(n-1),u_(3)=x^(n-2),...,u_(n)=x," then "u_(1)'.u_(2)'.u_(3)...u_(n)'=

Calculate the (i) mass defect, (ii) binding energy and (iii) the binding energy per nucleon of ""_(6)^(12)C nucleus. Nuclear mass of ""_(6)^12C = 12. 000000 u, mass of proton=1.007825 u and mass of neutron=1.008665 u.

If u_(1), u_(2), u_(3),… form a G.P. with common ratio k, find the sum of u_(1)u_(2) + u_(2)u_(3)+….+u_(n)u_(n+1) in terms of u_(1) and k.