Find the maximum distance of any point on the curve `x^2+2y^2+2x y=1` from the origin.

The minimum distance of a point on the curve y=x^2-4 from origin ,

If the maximum distance of any point on the ellipse x^(2)+2y^(2)+2xy=1 from its center is r, then r is equal to

The minimum distance of a point on the curve y=x^(2)-4 from the origin is :

The maximum distance of the point (a, 0) from the curve 2x^(2) + y^(2) - 2x = 0 is -

The maximum distance of the point (4,4) from the circle x^2+y2-2x-15=0 is

The maximum distance of the point (k,0) from the curve 2x^(2)+y^(2)-2x=0 is equal to

The distance of the centre of the sphere x^2 + y^2 + z^2 - 2x - 4y = 0 from the origin is