`PQ` is a chord of length 8 cm, of a circle with centre O and of radius 5 cm. The tangents at P and Q intersect at a point T. The length of TP is
Text Solution
Verified by Experts
`OR^2 +PR^2 = OP^2`
`OR = 3cm`
Now, from similarity of triangles
`(TP)/(PO) = (RP)/(RO)`
`TP = 20/3 cm`
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