The velocity of a body moving in a straight line is given by `v=(3x^(2)+x)m//s` . Find acceleration at `x=2m`.

A partical is moving in a straight line such that ita velocity is given by v=t^(4)+3t^(2)+8 m//s . Find acceleration at time t=1 s .

The initial velocity of a body moving along a straight lines is 7m//s . It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-

The initial velocity of a body moving along a straight lines is 7m//s . It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-

The velocity function of an object moving along a straight line is given by v(t)=At^(2)+Bt . If at t=2s, the velocity is 3 m/s and acceleration is 0.500 m//s^(2) , find the value of the constant A.

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

The velocity v of a body moving along a straight line varies with time t as v=2t^(2)e^(-t) , where v is in m/s and t is in second. The acceleration of body is zero at t =

Velocity of particle moving along x-axis is given as v = ( x^(3) - x^(2) + 2) m // sec. Find the acceleration of particle at x=2 meter.

Velocity of particle moving along x-axis is given as v = ( x^(3) - x^(2) + 2) m // sec. Find the acceleration of particle at x=2 meter.

The velocity-position graph of a particle moving in a straight line along x-axis is given below. Acceleration of particle at x = 2 m is

If the velocity of a particle is given by v=(180-16x)^((1)/(2))(m)/(s) , then its acceleration will be