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if A+B+C=pi then cosA/(sinBsinC)+cosB/...

if `A+B+C=pi` then `cosA/(sinBsinC)+cosB/(sinCsinA)+cosC/(sinAsinB)=`

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If A + B + C= pi , prove that cosA/(sinBsinC)+cosB/(sinCsinA)+cosC/(sinAsinB)=2

If A+B+C=pi prove that (cosA)/(sinBsinC)+(cosB)/(sinCsinA)+(cosC)/(sinAsinB)=2 .

If A+B+C=180^(@) then prove that the following: (cosA)/(sinBsinC)+(cosB)/(sinCsinA)+(cosC)/(sinAsinB)=2

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Prove that (sin(B-C))/(sinB.sinC) + (sin(C-A))/(sinCsinA) + (sin(A-B))/(sinA.sinB) = 0