A normal at `P(x , y)` on a curve meets the x-axis at `Q` and `N` is the foot of the ordinate at `Pdot` If `N Q=(x(1+y^2))/(1+x^2)` , then the equation of curve given that it passes through the point `(3,1)` is

Find the equation of the normal to curve x^(2)=4y which passes through the point (1,2)

If f'(x)=x-1, the equation of a curve y=f(x) passing through the point (1,0) is given by

Find the equation of the normal to the curve x^(2)=4y which passes through the point (1,2).

Equation of the normal to the curve y=-sqrt(x)+2 at the point (1,1)

If slope of the tangent at the point (x, y) on the curve is (y-1)/(x^(2)+x) , then the equation of the curve passing through M(1, 0) is :

A normal is drawn at a point P(x,y) of a curve.It meets the x-axis and the y-axis in point A AND B, respectively,such that (1)/(OA)+(1)/(OB)=1, where O is the origin.Find the equation of such a curve passing through (5,4)

The slope of the tangent at (x,y) to a curve passing through a point (2,1) is (x^(2)+y^(2))/(2xy) then the equation of the curve is

Tangent at P(2,8) on the curve y=x^(3) meets the curve again at Q.Find coordinates of Q.