The radius of `Na^(+)` is 95pm and that of `Cl^(-)` is 181 pm. The edge length of unit cell in NaCl would be (pm).

The radius of Na^(+) is 95 pm and that of CI^(-) ion is 181 pm. Hence the co-ordination number of Na^(+) will be

The radius of K^(+) is 133 pm and that of Cl^- is 181 pm. The volume of the unit cell of KCI expressed in 10^(-22) cm^(3) is :

The radius of Na^(+) ion is 95 pm and that of Cl^(-) ion is 181 pm. Predict the structure of Na^(+)Cl^(-) and the coordination number of cation.

The radius of the Na^(+) is 95 pm and that of Cl^(-) ion is 181 pm. Predict the coordination number of Na^(+)

If the radius of Cl^(+) ion 181pm, and the radius of Na^(+) ion is 101pm then the edge length of unit cell is:

The radius of Na(+) is 95 pm and that of CI^(-) ions is 181 pm. Predict whethr the coordination number of Na^(+) is 6 or4.