The curve with the property that the projection of the ordinate on the normal is constant and has a length equal to `a` is

Find the curve for which the perpendicular from the foot of the ordinate to the tangent is of constant length.

Find the equation of a curve such that the projection of its ordinate upon the normal is equal to its abscissa.

Find the equation of a curve such that the projection of its ordinate upon the normal is equal to its abscissa.

A curve y=f(x) has the property that the perpendicular distance of the origin from the normal at any point P of the curve is equal to the distance of the point P from the x-axis. Then the differential equation of the curve

The projection of a line segment on the co-ordinate 3, 4, 5, then its length is

A curve passing through the point (1,2) has the property that the perpendicular distance of the origin from normal at any point P of the curve is equal to the distance of P from the x-axis is a circle with radius.

At any point on the curve y=f(x), the length of the sub normal is constant, then the curve is

Find the equation of the curve for which the length of the normal is constant and the curves passes through the point (1,0).

A curve is such that the area of the region bounded by the co-ordinate axes,the curve delta the coordinate of any point on it is equal to the cube of that ordinate.The curve represents