The capacitance of a parallel plate capacitor is `12 muF`. If the distance between the plates is doubled and area is halved, then new capacitance will be

The capacitance of an air filled parallel plate capacitor is 10 muF . The separation between the plates is doubled and the space between the plates is then filled with wax giving the capacitance a new value of 40 xx 10^(-12) farads. The dielectirc consatnt of wax is

The capacity of a parallel plate condenser is 12muF . Its capacity, when the separation between plates is doubled and area is halved will be

To reduce the capacitance of parallel plate capacitor, the space between the plate is

To reduce the capacitance of parallel plate capacitor, the space between the plate is

The capacitance of a parallel plate air capacitor is 10 mu F .If now the overlapping area of plates is doubled and separation between the plates is halevd then new capacitance is:-

The capacitance of a parallel plate air capacitor is 10 mu F .If now the overlapping area of plates is doubled and separation between the plates is halevd then new capacitance is:-

What happens to the capacitance of a parallel plate capacitor if the area of its plates is doubled ?

What will be the change in the capacitance of a parallel plate capacitor, if the surface area of its plates is doubled and separation between plates doubled?