The specific conductance of a solution is 0.03568 ohm/cm and when placed in a cel, the conductance is 0.0268 per ohm. The cell constant is

The specific conductance of a solution is 0.3568 " ohm"^(-1) cm^(-1) when placed in a cell the conductance is 0.0268 " ohm"^(-1) . The cell constant is

The specific conductance of a solution is 0.356 ohm^-1 cm^-1 . The conductance of this solution in a cell was 0.0268 ohm^-1 . Calculate the cell constant.

At 25^@ C specific conductivity of a normal solution of KCI is 0. 0022765 ohm. The resistance of cell is 400 ohms. The cell constant is .

At 25^@ C specific conductivity of a normal solution of KCl is 0. 0022765 ohm. The resistance of cell is 400 ohms. The cell constant is

Area of each electrode of a conductivity cell is "1.25 cm"^(2) . The cell is filled with a solution of resistance of 160 ohm. If specific conductance of the solution is "0.016 ohm"^(-1)."cm"^(-1) , calculates the distance between the electrodes, and the cell constant.

The specific conductance of a 0.1 N KCI solution at 25^@ C is 0.015 ohm^ (-1) cm^(-1) . The resistances of the cell containing the solution at the same temperature was found to be 60 Omega . The cell constant (in cm^(-1)) will be

The specific conductance of a 0.1 N KCI solution at 25^@ C is 0.015 ohm^ (-1) cm^(-1) . The resistances of the cell containing the solution at the same temperature was found to be 60 Omega . The cell constant (in cm^(-1)) will be

The specific conductivity of 0.5N solution is 0.01287 ohm^(-1) cm^(-1) . What would be its equivalent conductance?