If a line is passing through `p(2,3)` which intersects the line `x+y=7` at a distance of four units from `P`. Then the slope of line is

Slope of a line passing through P(2,3) and intersecting the line, x+y=7 at a distance of 4 units from P , is

A line passing through the point P (1, 2) meets the line x+y=7 at the distance of 3 units from P. Then the slope of this line satisfies the equation

A line passing through the point P(1,2) meets the line x+y=7 at the distance of 3 units from P. Then the slope of this line satisfies the equation :

A line passing through A(1, -2) has slope 1. The points on the line at a distance of 4sqrt(2) unit from A are

The equation of the line passing through the point of intersection of the lines 2x+y-4=0, x-3y+5 =0 and lying at a distance of sqrt5 units from the origin, is

The equation of the line passing through the point of intersection of the lines 2x+y-4=0, x-3y+5 =0 and lying at a distance of sqrt5 units from the origin, is

A line with positive rational slope, passes through the point A(6,0) and is at a distance of 5 units from B (1,3). The slope of line is

A line with positive rational slope, passes through the point A(6,0) and is at a distance of 5 units from B (1,3). The slope of line is

A line with positive rational slope, passes through the point A(6,0) and is at a distance of 5 units from B (1,3). The slope of line is