A curve passes through the point `(1,pi/6)` . Let the slope of the curve at each point `(x , y)` be `y/x+sec(y/x),x > 0.` Then the equation of the curve is

A curve passes through the point (1,(pi)/(6)). Let the slope of the curve at each point (x,y) be (y)/(x)+sec((y)/(x)),xgt0. Then, the equation of the curve is

A curve passes through the point (3,-4) and the slope of.the is the tangent to the curve at any point (x,y) is (-(x)/(y)) .find the equation of the curve.

A curve passes through the point (2,0) and the slope of the tangent at any point (x, y) is x^(2)-2x for all values of x then 6y_(max) is equal to

A curve passes through the point (2,-8) and the slope of tangent at any point (x,y) is given by x^(2)/2-6x . The maximum ordinate on the curve is given by lambda then find (3lambda ).

If slope of the tangent at the point (x, y) on the curve is (y-1)/(x^(2)+x) , then the equation of the curve passing through M(1, 0) is :

If a curve passes through the point (1, -2) and has slope of the tangent at any point (x,y) on it as (x^2-2y)/x , then the curve also passes through the point