An organic compound has the following percentage composition , `C = 48 %, H = 8 %, N = 28 %`. Calculate the empirical formula of the compound.

An organic compound has the following percentage composition : C= 48%, H= 8% N= 28% and rest of oxygen. Calculate the empirical formula of the compound.

A chemical compound is found to have the following composition : C = 19.5%, Fe = 15.2%, N = 22.8%, K = 42.5% Calculate the empirical formula of the compound. What will be the molecular formula if the molecular mass of the compound is 368 ?

A laboratory analysis of an organic compound gives the following mass percentage composition: C = 60%, H = 4.48% and remaining oxygen. Find out the Empirical Formula of the compound.

A compound on analysis gave the following percentage composition: C = 24.47%, H= 4.07 %, Cl = 71.65%. Find out its empirical formula.

The percentage composition of a compound is C = 10%, Cl= 89.2%, H = 0.84%. Empirical formula of the compound is

Calculate the empirical and molecular formula of the compound having the following percentage composition : Na = 36.5%, H = 0.8%, P = 24.6%, O = 38.1% The molecular mass of the compound is 126 a.m.u. Also name the compound