`H_(2)O_(2)` can be produced by the ammonium hydrogen sulphate. Reactions occuring in electrolytic cell,
`NH_(4)HSO_(4)rarrNH_(4)^(-)+2e^(-)` (Anode)
`2SO_(4)^(2-)rarrS_(2)O_(8)^(2-)+2e^(-)`
`2H^(+)+2e^(-)rarrH_(2)` (Cathode)
Hydrolysis of ammonium persulphate:
`(NH_(4))_(2)S_(2)O_(8)+2H_(2)Orarr2NH_(4)HSO_(4)+H_(2)O_(2)` Assume 100% yield of hydrolysis reaction.
What volume of hydrogen gas at 1 atm and 273 K will be produced in cathode in previous question?

H_(2)O_(2) can be produced by the ammonium hydrogen sulphate. Reactions occuring in electrolytic cell, NH_(4)HSO_(4)rarrNH_(4)^(-)+2e^(-) (Anode) 2SO_(4)^(2-)rarrS_(2)O_(8)^(2-)+2e^(-) 2H^(+)+2e^(-)rarrH_(2) (Cathode) Hydrolysis of ammonium persulphate: (NH_(4))_(2)S_(2)O_(8)+2H_(2)Orarr2NH_(4)HSO_(4)+H_(2)O_(2) Assume 100% yield of hydrolysis reaction. How many "mole"s of electrons are to be passed in order to produce enough H_(2)O_(2) which when reacted with excess of KI then liberated iodine required 100 mL of centimolar hypo solution.

H_(2)O_(2) can be produced by the ammonium hydrogen sulphate. Reactions occuring in electrolytic cell, NH_(4)HSO_(4)rarrNH_(4)^(-)+2e^(-) (Anode) 2SO_(4)^(2-)rarrS_(2)O_(8)^(2-)+2e^(-) 2H^(+)+2e^(-)rarrH_(2) (Cathode) Hydrolysis of ammonium persulphate: (NH_(4))_(2)S_(2)O_(8)+2H_(2)Orarr2NH_(4)HSO_(4)+H_(2)O_(2) Assume 100% yield of hydrolysis reaction. What is the current efficiency when 100 Amp current is passed for 965 seconds in order to produce 17 gm of H_(2)O_(2) .

H_(2)O_(2) can be produced by the Ammonium hydrogen sulphate. Reactions occuring in electrolytic cell. NH_(4)HSO_(4) rarr NH_(4)^(+) +H^(+) +SO_(4)^(2-) 2SO_(4)^(2-) rarr S_(2)O_(8)^(2-) +2e^(-) (Anode) 2H^(+) +2e^(-) rarr H_(2) (cathode) (NH_(4))_(2)S_(2)O_(8) +2H_(2)O rarr 2NH_(4)HSO_(4) +H_(2)O_(2) Hydrolysis of Ammonium persulphate Assume 100% yield of hydrolysis reaction. How many moles of electrons are to be passed in order to produce enough H_(2)O_(2) which when reacted with excess of KI then liberated iodine required 100 ml of centimolar Hypo solution.

H_(2)O_(2) can be produced by the Ammonium hydrogen sulphate. Reactions occuring in electrolytic cell. NH_(4)HSO_(4) rarr NH_(4)^(+) +H^(+) +SO_(4)^(2-) 2SO_(4)^(2-) rarr S_(2)O_(8)^(2-) +2e^(-) (Anode) 2H^(+) +2e^(-) rarr H_(2) (cathode) (NH_(4))_(2)S_(2)O_(8) +2H_(2)O rarr 2NH_(4)HSO_(4) +H_(2)O_(2) Hydrolysis of Ammonium persulphate Assume 100% yield of hydrolysis reaction. What is the current efficiency when 100 Amp current is passed for 965 sec, in order to produce 17 gm of H_(2)O_(2) .

H_(2)O_(2) can be produced by the Ammonium hydrogen sulphate. Reactions occuring in electrolytic cell. NH_(4)HSO_(4) rarr NH_(4)^(+) +H^(+) +SO_(4)^(2-) 2SO_(4)^(2-) rarr S_(2)O_(8)^(2-) +2e^(-) (Anode) 2H^(+) +2e^(-) rarr H_(2) (cathode) (NH_(4))_(2)S_(2)O_(8) +2H_(2)O rarr 2NH_(4)HSO_(4) +H_(2)O_(2) Hydrolysis of Ammonium persulphate Assume 100% yield of hydrolysis reaction. What is the current efficiency when 100 Amp current is passed for 965 sec, in order to produce 17 gm of H_(2)O_(2) .

Anodic oxidation of ammonium hydrogen sulphate produces ammonium persulphate. NH_(4) HSO_(4) rarr NH_(4)SO_(4)^(-) + H^(+) 2NH_(4) SO_(4)^(-) rarr (NH_(4))_(2) S_(2) O_(8) + 2e^(-) (Anodic oxidation) 2H^(+) + 2e^(-) rarr H_(2) (Cathodic reduction) Hydrolysis of ammonium persulphate forms H_(2)O_(2) (NH_(2))_(2) S_(2)O_(8) + 2H_(2)O rarr 2NH_(4) HSO_(4) + H_(2)O_(2) Current efficiency in electrolytic process is 60%. Calculate the amount of current required to produce 85 g of H_(2)O_(2) per hour: Hydrolysis reaction shows 100% yield.

Give the percentages of ammonium and sulphate radicals in Mohr salt [(NH_(4))_(2)SO_(4)*FeSO_(4)*6H_(2)O] .