A curve passing through `(2,3)` and satisfying the differential equation `int_0^x ty(t)dt=x^2y(x),(x >0)` is

The equation of a curve passing through the origin and satisfying the differential equation (dy)/(dx)=(x-y)^(2) , is

The equation of the curve passing through (3,4) and satisfying the differential equation. y((dy)/(dx))^(2)+(x-y)(dy)/(dx)-x=0 can be

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

Find the equation of the curve passing through origin and satisfying the differential equation 2xdy = (2x^(2) + x) dx .

Equation of curve passing through (1, 1) and satisfying the differential equation (dy)/(dx) =(2y) /(x) , ( where x gt 0 , y gt 0 ) is given by :

The equation of the curve passing through the origin and satisfying the differential equation ((dy)/(dx))^(2)=(x-y)^(2) , is

The equation of curve passing through origin and satisfying the differential equation (1+x^(2))(dy)/(dx)+2xy=4x^(2), is

Let a curve passes through (3, 2) and satisfied the differential equation (x-1) dx + 4(y -2) dy = 0

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1