Two samples A and B of the same gas have equal volumes and pressures . The gas is sample A is expanded isothermally to double its volume and the the gas in B is expanded adibatically to double its volume . If the work done by the gas is the same for the two cases, show that gamma satisfies the equation`(1-2 ^(1-gamma)= (gamma - 1 ) 1n2`.

Two samples A and B of the same gas have equal volumes and pressure. The gas in sample A is expanded isothermally to four times of its initial volume and the gas in B is expanded adiabatically to double its volume. It work done in isothermal process is twice that of adiabatic process, then show that gamma satisfies the equation 1-2^(1-gamma) =(gamma-1)In2 .

An ideal gas at 300K is expanded isothermally to double its volume,then pressure of the gas will be

An ideal gas at 300K is expanded isothermally to double its volume, then pressure of the gas will be

One mole of ideal gas expands isothermally to double its volume at 27^(@)C . Then the work done by the gas is nearly

One mole of an ideal gas expands isothermally to double its volume at 27^(@)C . The work done by the gas is nearly

5 mole of an ideal gas of volume is expanded against vaccum to make its volume 2 times, then work done by the gas is:

5 mole of an ideal gas of volume is expanded against vaccum to make its volume 2 times, then work done by the gas is:

Two moles of an ideal monoatomic get at 27^(@)C occupies a volume of V. If the gas is expanded adiabatically to the volume 2V, then the work done by the gas will be (gamma=5//3)

1g H_(2) gas at STP is expanded so that volume is doubled. Hence, work done is