A particle of charge per unit mass `alpha` is released from origin with a velocity `vecv=v_(0)hati` in a magnetic field
`vec(B)=-B_(0)hatk` for `xle(sqrt(3))/2 (v_(0))/(B_(0)alpha)`
and `vec(B)=0` for `xgt(sqrt(3))/2 (v_(0))/(B_(0)alpha)`
The `x`-coordinate of the particle at time `t((pi)/(3B_(0)alpha))` would be

A particle of charge per unit mass alpha is released from origin with velocity vec v = v_0 hat i in a magnetic field vec B = -B_0 hat k for x le sqrt 3/2 v_0/(B_0 alpha) and vec B = 0 for x gt sqrt 3/2 v_0/(B_0 alpha) The x-coordinate of the particle at time t(gt pi/(3B_0 alpha)) would be

A particle of charge per unit mass alpha is released from origin with a velocity vecv=v_(0)hati uniform magnetic field vecB=-B_(0)hatk . If the particle passes through (0,y,0) , then y is equal to

A particle of charge per unit mass alpha is released from origin with a velocity vecv=v_(0)hati uniform magnetic field vecB=-B_(0)hatk . If the particle passes through (0,y,0) , then y is equal to

A proton is fired from origin with velocity vecv=v_0hatj+v_0hatk in a uniform magnetic field vecB=B_0hatj .

A particle of specific charge 'alpha' is projected from origin at t=0 with a velocity vec(V)=V_(0) (hat(i)-hat(k)) in a magnetic field vec(B)= -B_(0)hat(k) . Then : (Mass of particle =1 unit)

A particle of charge per unit mass alpha is released from the origin with velocity v=v_(0)hati in the magnetic field vecB=-B_(0)hatk for A cup of tea cools from 80^(@)C" to "60^(@)C in 40 seconds. The ambient temperature is 30^(@)C . In cooling from 60^(@)C" to "50^(@)C , it will take time: x le (sqrt3)/(2)(v_(0))/(B_(0)alpha) and vecB=0" for "x gt (sqrt3)/(2)(v_(0))/(B_(0)alpha) The x - coordinate of the particle at time t(gt(pi)/(3B_(0)alpha)) would be

A charged particle (q.m) released from origin with velocity v=v_(0)hati in a uniform magnetic field B=(B_(0))/(2)hati+(sqrt3B_(0))/(2)hatJ . Maximum z-coordinate of the particle is

A charged particle (q.m) released from origin with velocity v=v_(0)hati in a uniform magnetic field B=(B_(0))/(2)hati+(sqrt3B_(0))/(2)hatJ . Maximum z-coordinate of the particle is