A particle is thrown vertically upward from the ground with some velocity and it strikes the ground again in time 2 s. The maximum height achieved by the particle is : `(g=10 m//s^(2))`

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball in thrown vertically upwards from the ground with some velocity. The velocity of the particle at one fourth of the maximum height is 10sqrt(3) m//s . Then choose option(s) (g = 10 m//s^(2))

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

When a particle is thrown vertically upwards, its velocity at one third of its maximum height is 10sqrt2m//s . The maximum height attained by it is

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?

A particle is projected vertically upwards from ground with velocity 10 m // s. Find the time taken by it to reach at the highest point ?

A particle is thrown vertically upwards. If its velocity is half of the maximum height is 20 m//s , then maximum height attained by it is

A particle is thrown vertically upwards. If its velocity is half of the maximum height is 20 m//s , then maximum height attained by it is