A point source, of electromagnetic radiation has average power output of `800` W. The maximum value electric at a distance `4.0` m from the source is:

A point source of electromagnetic radiation has an average power output of 800 W . The maximum value of elecvtric field at a distance 4.0 m from the source is

A point source of electromagnetic radiation has an average power output of 800W. The mximum value of electric field at a distance 3.5 m from the source will be 62.6 V/m, the maximum value of magnetic field will be -

A point source of electromagnetic radiation has an average power output of 800W . The maximum value of electric field at a distance 3.5m from the source will be 62.6 V/m , the energy density at a distance 3.5 m from the source will be- (in "joule"//m^(3) )

A point source of electromagnetic radiation has an average power output of1500W. The maximum value of electric field at a distance 3m from this source in Vm^-1 is

A point source of electromagnetic radiation has an average power output of 800W. (a) Find the maximum value of electric field at a distance 3.5 m from the source. (b) What will be the maximum value of magnetic field? (c) What will be the energy density at a distance at a distance 3.5m from the source?

A point source of electromagnetic rediation has an average power output of 960 W. The peak value of the electric field at a distance 400 cm from the source is

A point source of electromagnetic radiaction has average power output of 800 watt. Then find (a) Maximum value of electric field at a distance 3.5m from the source (b) Maximum vatue of magnetic field (c) Average energy density at 3.5 m from the source.