Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take `g = 10 ms^(-2)`.

Projection angle with the horizontal is :

Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take g = 10 ms^(-2) . , The projection speed is :

Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take g = 10 ms^(-2) . , The projection speed is :

Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take g = 10 ms^(-2) . , Maximum height attained from the point of projection is

Two graphs of the same projectile motion (in the xy-plane) projected from origin are shown. X-axis is along horizontal direction and y-axis is vertically upwards. Take g = 10 ms^(-2) . , Maximum height attained from the point of projection is

Two graphs of the same projectile motion (in the x - y plane) projected from origin are shown in (Fig. 5 .10). X - axis is along horozontal direction and Y - axis is vertically upwards. Take g = 10 m s^2 Find (i) The y component of initial velocity and (ii) the X component of initial velocity. .

A projectile is projected in the upward direction making an angle of 45^@ with horizontal direction with a velocity of 150 ms^(-1) . Then the time after which its inclination with the horizontal is 30^@ is (g=10 ms^(-2)).

At a height of 0.4 m from the ground, the velocity of projectile in vector from is vec(u)=(6hat(i)+2hat(j)) (the x-axis is horizontal and y-axis is vertically upwards). The angle of projection is : (g = 10 m//s^(2))

A particle is projected from origin in xy-plane and its equation ,of trajectory is given by y = ax - bx^(2) . The only acceleration ,in the motion is' f' which is constant and in -ve direction of, y-axis. (a) Find the velocity of projection and the angle of projection. (b) Point of projection is considered as origin and x-axis along the horizontal ground. Find the horizontal range: and maximum height of projectile. Projectile completes its flight in horizonal plane of projection.