At 300 K the vapour pressure of two pure liquids, A and B are 100 and 500 mm Hg, respectively. If in a mixture of a and B, the vapoure is 300 mm Hg, the mole fractions of a in the vapour phase, respectively, are -

At 300 K, two pure liquids A and B have vapour pressures 150 mm Hg and 100 mm Hg respectively. In an equimolar liquid mixture of A and B, the mole fraction of B in the vapour mixture at this temperature is:

At a particular temperature, the vapour pressure of two liquids A and B are 120 and 180 mm Hg respectively. If 2 mole of A and 3 mole of B are mixed to form an ideal solution, the vapour pressure of the solution at the same temperature will be (in mm Hg)

The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour pressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-

The vapour pressure of pure liquid A and liquid B at 350 K are 440 mm and 720 mm of Hg. If total vapour [ressure of solution is 580 mm of Hg then the mole fraction of liquid A in vapour phase will be :-

The vapour pressure of pure liquids A and B are 450 and 700mm Hg respectively, at 350K.Find out the composition of the liquid mixture if total vapour pressure is 600 mm Hg. Also find the composition of the vapure phase.

The vapour pressure of pure liquids A and B are 450 mm Hg and 700 mm Hg, resprectively at 350 K. Find the composition of liquid and vapour if total vapour pressure is 600 mm. Hg.

The vapour pressure of A and B at 25 ^(@) C are 90 mm Hg and 15 mm Hg respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x x 10 ^(-1) The value of x is ___________. (Nearest integer)