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A chord of a circle of radius 10 cm subt...

A chord of a circle of radius `10` cm subtends a right angle at the centre. Find the area of the corresponding :
(i) minor segment
(ii) major sector.

Text Solution

AI Generated Solution

To solve the problem, we need to find the area of the minor segment and the major sector of a circle with a radius of 10 cm, where a chord subtends a right angle (90 degrees) at the center. ### Step 1: Calculate the Area of the Minor Sector The area of the minor sector can be calculated using the formula: \[ \text{Area of sector} = \frac{\theta}{360} \times \pi r^2 \] where \(\theta\) is the angle in degrees and \(r\) is the radius. ...
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Knowledge Check

  • A chord of circle of a radius 28 cm subtends a right angle at the centre. What is the area of the minor sector?

    A
    `621 cm^(2)`
    B
    `616 cm^(2)`
    C
    `718 cm^(2)`
    D
    `721 cm^(2)`
  • A chord of a circle of radius 10 cm subtends a right angle at the centre. The area of the minor segments (given pi=3.14) is

    A
    `32.5cm^(2)`
    B
    `34.5cm^(2)`
    C
    `28.5cm^(2)`
    D
    `30.5cm^(2)`
  • The chord of a circle of radius 10cm subtends a right angle at its centre. The length of the chord (in cm) is

    A
    `(5)/(sqrt(2))`
    B
    `5sqrt(2)`
    C
    `10sqrt(2)`
    D
    `10sqrt(3)`
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