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If 2 cos^2 theta +11 sin theta -7 = 0, t...

If `2 cos^2 theta +11 sin theta -7 = 0,` then `sin theta` is -

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Solve 2 cos^(2) theta + 11 sin theta = 7

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(cos theta + sin theta )^(2) + (cos theta - sin theta )^(2) =

(cos^(2)theta)/(sin theta)-cosec theta+sin theta=0