If `y = x^3 + tan x,` show that `(d^2y)/dx^2= 6x + 2 sec^2 tanx.`

Solve: (d^2y)/dx^2=6x+sec^2x

Solve: (d^2y)/dx^2=6x+sec^2x

If y= x + tan x , show that cos^2 x (d^2 y)/(dx^2) -2y + 2x =0

If y=x+tan x , show that cos^2 x (d^2y)/(dx^2)-2y+2x=0

If y=x+tanx , show that cos^2x\ (d^2y)/(dx^2)-2y+2x=0 .

If y=sec x -tan x ,then (d^(2)y)/(dx^(2)) =

If y = tan^-1 x , show that : (1+x^2) d^2y/dx^2+ 2x dy/dx=0

Find (dy)/(dx) , when If y = sqrt((sec x - tanx)/(sec x + tanx)) , show that (dy)/(dx) = sec x (tanx - sec x) .

If y = e^(3tan^-1 x) , then show that (1+x^2)^2 (d^2y)/(dx^2) + 2x(1+x^2)dy/dx = 9y