Home
Class 11
MATHS
The polynomial x^6+4x^5+3x^4+2x^3+x+1 is...

The polynomial `x^6+4x^5+3x^4+2x^3+x+1` is divisible by_______ where `w` is the cube root of units `x+omega` b. `x+omega^2` c. `(x+omega)(x+omega^2)` d. `(x-omega)(x-omega^2)` where `omega` is one of the imaginary cube roots of unity.

Promotional Banner

Similar Questions

Explore conceptually related problems

The polynomial x^6+4x^5+3x^4+2x^3+x+1 is divisible by_______ where omega is one of the imaginary cube roots of unity. (a) x+omega (b) x+omega^2 (c) (x+omega)(x+omega^2) (d) (x-omega)(x-omega^2)

The polynomial x^6+4x^5+3x^4+2x^3+x+1 is divisible by_______ where omega is one of the imaginary cube roots of unity. (a) x+omega (b) x+omega^2 (c) (x+omega)(x+omega^2) (d) (x-omega)(x-omega^2)

|{:(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega):}|=0 where omega is an imaginary cube root of unity.

The polynomial x^(6)+4x^(5)+3x^(4)+2x^(3)+x+1 is divisible by: (where omega is one of the imaginary cube roots of unity)

Evalute: |{:(1,omega^3,omega^2),(omega^3,1,omega),(omega^2,omega,1):}| , where omega is an imaginary cube root of unity .

If omega is a cube root of unity , then |(x+1 , omega , omega^2),(omega , x+omega^2, 1),(omega^2 , 1, x+omega)| =

If omega is a cube root of unity , then |(x+1 , omega , omega^2),(omega , x+omega^2, 1),(omega^2 , 1, x+omega)| =

If omega is a cube root of unit, then Delta=|(x+1,omega, omega^(2)),(omega, x+omega^(2),1),(omega^(2),1,x+omega)|=

The value of |(1,omega,2omega^(2)),(2,2omega^(2),4omega^(3)),(3,3omega^(3),6omega^(4))| is equal to (where omega is imaginary cube root of unity