`lim_(x->oo)((x+2)^(10)+(x+4)^(10)++(x+20)^(10))/(x^(10)+1)=`

lim_(x rarr oo) ((x+2)^(10)+(x+4)^(10)+...+(x+20)^(10))/(x^(10)+1)= ______.

lim_(xtooo) ((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to

lim_(xtooo) ((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to

lim_(xrarroo)((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to (a) 0 (b) 1 (c) 10 (d) 100

lim_(xrarroo)((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to (a) 0 (b) 1 (c) 10 (d) 100

Lt_(x to oo) ((x+1)^(10)+(x+2)^(1)....+(x+50)^(10))/(x^(10)-10^(10))

lim_(x rarr oo x rarr oo)((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10))

underset(x to oo)lim ((x+1)^(10)+(x+2)^(10)+...+(x+10)^(10))/(x^(10)+10^(10))=...

If underset(xrarroo)"lim"((1+x)^(10)+(x+2)^(10)+....+(x+100)^(10))/(x^(10)+10^(10)) =K^(2) , then the value of K will be -

Statement-1 : lim_(xrarr oo) ((x+1)^10+(x+2)^10+.....+(x+100)^(10))/(x^10+9^10) =100 Statement -2 : If f(x)and g(x) are polynomials of same degree, then lim_(xrarroo) (f(x))/(g(x))=("Coefficient of leading term in" f(x))/("Coefficient of leading term in" g(x))