`lim_(x->oo)(2+6+10+14+......2n terms)/(2+4+6+8+....n terms)`

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lim_(n rarr oo) (2+6+10+14+..."2n terms")/(2+4+6+8+..."n terms")= ______.

lim_(n rarr oo) (1+3+5+7+...."n terms")/(2+4+6+8+...."n terms")= _____.

2 . 4+4 . 6+6 . 8+... to n terms =

2+3+5+6+8+9+…...2n terms =

2+3+5+6+8+9+........2n terms =

Sum to n terms of 2+4+6+8 ..=

3.6+4.7+5.8+.....+(n-2) terms =

If (1 + 3 + 5 + 7 …. Up to n terms) / (2 + 4 + 6 + 8 +… up to n terms)= 0.95, find n.

underset(n to oo)lim ((1+2+....+"n terms")(1^(2)+2^(2)+...+"n terms"))/(n(1^(3)+2^(3)+...+"n terms"))=

2.4+4.7+6.10+....(n-1)terms=