A particle is ejected from the tube at A with a velocity `V` at an angle `theta` with the verticle y-axis at a height h above the ground as shown. A strong horizontal wind gives the particle a constant horizontal acceleration a in the positive x-direction. If the particle strikes the ground at a point directly under its released position and the downward y-acceleration is taken as g then find h.

A particle Is projected at point 'A' with initial velocity 5 m//s at an angle theta = 37^(@) with the vertical y axis. A strong horizontal wind gives the particle a constant horizontal acceleration 6 m//s^(2) in the x direction. If the particle strikes the ground at a point directly under its released position, determine the height 'h' of point A . The downward acceleration is taken as the constant g = 10 m//s^(2) (take sin37^(@) = (3)/(5), cos37^(@) = (4)/(5) )

A particle Is projected at point 'A' with initial velocity 5 m//s at an angle theta = 37^(@) with the vertical y axis. A strong horizontal wind gives the particle a constant horizontal acceleration 6 m//s^(2) in the x direction. If the particle strikes the ground at a point directly under its released position, determine the height 'h' of point A . The downward acceleration is taken as the constant g = 10 m//s^(2) (take sin37^(@) = (3)/(5), cos37^(@) = (4)/(5) )

A particle is projected from the ground with velocity u making an angle theta with the horizontal. At half of its maximum heights,

Velocity of a particle is in negative direction with constant acceleration in positive direction. Then match the following: