If the displacement `x` and velocity `v` of a aprticle executing `SHM` are related as `4v^(2) = 25 - x^(2)`. Then its maximum displacement in metre `(x, v` are in `SI`) is

Dispalcement (x) and velocity (v) of a particle exectuting S.H.M are related as 2v^(2)=9-x^(2) . The time period of particle is

If the displacement (x) and velocity (v) of a particle executing SHM are related through the expression 3v^(2)=30-x^(2) . If the time period of the particle is T=pisqrt(n) , then what is the value of n?

If the displacement (x) and velocity (v) of a particle executing SHM are related through the expression 3v^(2)=30-x^(2) . If the time period of the particle is T=pisqrt(n) , then what is the value of n?

If the displacement (x) and velocity (v) of a particle executing SHM are related through the expression 4v^(2)=25-x^(2) , what should be the value of (T//pi) ? [T is the time period (in second) of the SHM.]

If the displacement (y in m) and velocity (v in ms^(-1)) of a particle executing SHM are related by the equation 4v^(2)=16-y^(2) , then the path length of the motion and time period of oscillation respectively are