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Resistance of a conductor is twice that ...

Resistance of a conductor is twice that of another conductor and the potential differences between the two ends of the two conductors are same. Find the ratio of strengths of currents flowing through them.

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Let the resistance of the first conductor is 2R. So, resistance of the second conductor is R. If the terminal potential difference of both the conductors be V and if the strength of current flowing through them are `I_(1) and I_(2)` respectively, then `V=I_(1)xx2R and V=I_(2)xxR`
`therefore I_(1)xx2R=I_(2)xxR therefore (I_(1))/(I_(2))=(1)/(2)`
`therefore` The ratio of strength of current flowing through two conductors = 1: 2.
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