To what temperature must a gas at 300K be cooled in order to reduce its volume to `(1)/(3)th` of its original volume, pressure remaining constant.

Explanation

Pressure is constant means Charles. law can be applied.
Let, final temperature is `TK(T_(2))`, initial temperature is `300K(T_(1))`, Initial volume is `V(V_(1))` and final volumes is `(V)/(3)(V_(2))`
Then from Charles. law we have, `(V_(1))/(T_(1))=(V_(2))/(T_(2))or, (V)/(300)=(V)/(3)times(1)/(T) or, T=(300)/(3)=100K`
`therefore` Final temperature is 100K.