Establish gas equation, `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`.

Establish the equation : V_(-t) = V_0(1-t/(273))

State Boyle's and Charles's law Use these laws to derive the relationship (P_1V_1)/(T_1) = (P_2V_2)/T_2

A partical traveIIing with uniform acceleration along a straight line has average velocities v_(1),v_(2) and v_(3) in successive time intervals t_(1),t_(2) and t_(3) respectively . Prove that, (v_(2)-v_(1))/(v_(3)-v_(2))=(t_(1)+t_(2))/(t_(2)+t_(3))

(i) 1 mol of an ideal gas expands isothermally and reversible from (P_(1)V_(1)T) to (P_(2)V_(2)T) . Write down the equation showinig the amount of heat absorbed by the given ideal gas. (ii) In an isothermal expansion of an ideal gas, the pressure of the gas decreases from P_(1) to P_(2) . write down the equation of work done by the gas in this process. (iii) The temperature of 1 mol of an ideal gas is increased from T_(1) and T_(2) . write down the equations for the changes in enthalpy and internal energy.

If the normals at P(t_(1))andQ(t_(2)) on the parabola meet on the same parabola, then (A) t_(1)t_(2)=-1 (B) t_(2)=-t_(1)-(2)/(t_(1)) (C) t_(1)t_(2)=1 (D) t_(1)t_(2)=2

An ideal gas is compressed from state (P_(1), V_(1), T) to state (P_(2), V_(2), T) isothermally. What is the change in the internal energy of the gas? Answer with reason.

The initial pressure, temperature & volume of 1 mol of a gas are P_(1),T_(1) and V_(1) respectively. The state of the gas is changed by the following two ways. Will the internal energy change be the same in both cases? (1) P_(1)V_(1)T_(2) underset("Process")overset("Reversible")toP_(2)V_(2)T_(2) (2) P_(1)V_(1)T_(1) underset("process")overset("Irreversible")toP_(2)V_(2)T_(2) .

One mole of a mono atomic ideal gas undergoes a quasi -static process,s which is depicted by a straight line joining points (V_(0), T_(0)) and (2V_(0),3T_(0)) is a V-T diagram. What is the values of the heat capacity of the gas at the point (V_(0),T_(0)) ?