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Calculate the amount of sulphuric acid (...

Calculate the amount of sulphuric acid (75% by weight) which is needed to decompose 0.5 mole of calcium carbonate (Ca=40, C=12, S=32).

Text Solution

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`CaCO_(3)+H_(2)SO_(4) to CaSO_(4)+CO_(2)+H_(2)O`
`1mol e =1times2+32+16times4=98g`
Thus, 1mole of `CaCO_(3)` reacts with 98g of `H_(2)SO_(4)`
`therefore` 0.5 mole of `CaCO_(3)` reacts with `98times0.5` g of `H_(2)SO_(4)=49`g of `H_(2)SO_(4)`
Now, 75g of pure `H_(2)SO_(4)` is present in 100g of 75% `H_(2)SO_(4)`
`therefore` 49g of pure `H_(2)SO_(4)` is present in `(100)/(75)times49g=65.33g` of 75% of `H_(2)SO_(4)`
Hence the amounr of 75% `h_(2)SO_(4)` needed to decomposes 0.5 mol of `CaCO_(3)` is 65.33g`.
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