How much `KClO_(3)` is needed to produce enough oxygen for burning 10g of coke? (C=12, Cl=35.5, O=16)

Explanation

`underset(12g)(C)+underset(16times2g)(O_(2)) to CO_(2)`
Thus, 12g of coke requires 32g of oxygen for complete burning
`therefore` 10g of coke requires `(32times10)/(12)g=26.66g` of oxygen for complete burning.
Now, `underset(2(39+35.5+16times3)=245g)(2KClO_(3)) to KCl+underset(3times2times16=96g)(3O_(2))`
Thus 96g of oxygen is produced from 245g of `KClO_(3)`
`therefore` 26.66g of oxygen is produced from `(245times26.66)/(96)g=68.04`g of `KClO_(3)`
Hence, amount of `KClO_(3)` needed to produce enough `O_(2)` for burning 10g of coke is 68.04g.