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How much potassium chlorate is needed to...

How much potassium chlorate is needed to get enough oxygen for complete burning of 84g litre of carbon monoxide at STP?

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`underset(2(39+35.5+16times3)=245g)(2KClO_(3)) to 2KCl+underset("3mole")(3O_(2))`
`underset("2mole")(2CO)+underset("1mole")(O_(2)) to CO_(2)`
At STP, 1 mole of any gas occupies 22.4lL
Thus, 84 lit CO gas at STP contains`(84)/(22.4)=3.75` mole of CO
Now, 2 mole of CO 1 mole of `O_(2)` for complete burning.
3.75 mole of CO used `(3.75)/(2)=1.875` mole of `O_(2)` for complete burning
Again, 3mole of `O_(2)` require 245g of `KClO_(3)`
`therefore` 1.875 mole of `O_(2)` require `(245times1.875)/(3)g=153.125g` of `KClO_(3)`
Thus, 153.125g of `KClO_(3)` is needed to get enough oxygen for complete burning of 84 litres of carbon monoxide at STP.
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