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The weight of 1 litre of a gas at 27^(@)...

The weight of 1 litre of a gas at `27^(@) and 600` mm pressure is 0.8g. What is its vapour density and molecular weight?

Text Solution

Verified by Experts

Let the volume of the gas at STP be V ml
`therefore(Vtimes760)/(273)=(1000times600)/(273+27) or, V=718.4`ml
Thus, at STP 718.4 ml of the gas weighs 0.8g
`therefore` At STP 22400ml of the gas weighs `(0.8times22400)/(718.4)=24.944`g
`therefore` Gram molecular weight of the gas=24.944g
`therefore` The molecular weight of the gas=24.944
`therefore` The vapour density of the gas=`(24.944)/(2)=12.472`
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