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24 g of a solid element of requires 44.8...

24 g of a solid element of requires 44.8 litre of oxygen at STP for its complete conversion into a gaseous oxide. The gaseous oxide occupies a volume of 44.8 litre at STP. What is the weight of the gaseous oxide produced and what it its vapour density?

Text Solution

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22.4 lit of oxygen at STP correponds to 1 gram-mole of oxygen
`therefore` 44.8 lit of at STP corresponds to 2 gram-mole of oxygen
or `32times2=64g` of oxygen .
`therefore` The weight of the gaseous oxide=(24+64)=88g
Now, 88g of the gaseous oxide occupies a volume of 44.8 litre at STP
`therefore` 88g of the gaseous oxide occupies 2g mole of the oxide
`therefore` Mol.wt. of the oxide`=(88)/(2)=44`
`therefore` Vapour density of the oxide`=(44)/(2)=22`
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