In a potentiometer experiment the balancing length is 8 m, when the two cells `E_(1)` and `E_(2)` are joined in series. When the two cells are connected in opposition the balancing length is 4m. The ratio of the e.m.f. of two cells `(E_(1)//C_(2))` is

The balancing lengths for the cells of e.m.f. E_(1) and E_(2) are l_(1) and l_(2) respectively. If they are connected separately then

In a potentiometer experiment, the balancing length is found to be 1.8 m for a cell of e.m.f. 1.5 V. What is the balancing length for a cell of e.m.f. 1 V ?

Two cells of E.M.F. E_(1) and E_(2)(E_(2)gtE_(1)) are connected in series in the secondary circuit of a potentiometer experiment for determination of E.M.F. The balancing length is found to be 825 cm. Now when the terminals to cell E_(1) are reversed, then the balancing length is found to be 225 cm. The ratio of E_(1) and E_(2) is

Two cells of E.M.F. E_(1) and E_(2)(E_(2)gtE_(1)) are connected in series in the secondary circuit of a potentiometer experiment for determination of E.M.F. The balancing length is found to be 825 cm. Now when the terminals to cell E_(1) are reversed, then the balancing length is found to be 225 cm. The ratio of E_(1) and E_(2) is

In a potentiometer experiment, two cells connected in series get balanced at 9 m length of the wire. Now, if the connections of terminals of cell of lower emf are reversed, then the balancing length is obtained at 3 m. The ratio of emf's of two cells will be

In a potentiometer experiment, two cells of emf E_1 and E_2 are used in series in the secondary circuit. The balancing length is found to be 58 cm. If the polarity of E_2 is reversed, the balancing length becomes 29 cm. The ratio E_1//E_2 of the emfs of two cells is :

In a potentiometer experiment balancing for the first cell and second cell are 2.5 m and 2 m, respectively, when cells are used separately. Hence, E_1/E_2 is