Velocity and acceleration vector of a charged particle moving in a magnetic field at some instant are `vecv=3hati+4hatj and veca=2hati+xhatj`. Select the correct options.

Velocity and acceleration vectors of charged particle moving perpendicular to the direction of magnetic field at a given instant of time are vecv=2hati+chatj and veca=3hati+4hatj respectively. Then that value of 'c' is

Velocity and acceleration vectors of charged particle moving perpendicular to the direction of magnetic field at a given instant of time are vecV=2hati + c hatj and veca= 3hat i+4hat j respectively. Then value, of c is

A charged particle moves in a uniform magnetic field B=(2hati-3hatj) T

A charged particle moves in a uniform magnetic field B=(2hati-3hatj) T

Velocity and acceleration of a particle at some instant of time are v = (3hati +4hatj) ms^(-1) and a =- (6hati +8hatj)ms^(-2) respectively. At the same instant particle is at origin. Maximum x-coordinate of particle will be

Velocity and acceleration of a particle at some instant of time are v = (3hati +4hatj) ms^(-1) and a =- (6hati +8hatj)ms^(-2) respectively. At the same instant particle is at origin. Maximum x-coordinate of particle will be