Given
`C+2S rarr CS_(2), DeltaHf^(@)=+117.0 kJ mol^(-1)`
`C+O_(2) rarr CO_(2), DeltaHf^(@)=-393.0 kJ mol^(-1)`
`S+O_(2) rarr SO_(2), DeltaHf^(@)=-297.0 kJ mol^(-1)`
The heat of combustion of
`CS_(2)+3O_(2) rarr CO_(2)+2SO_(2)` is

Given C+ 2S rarr CS_(2), DeltaHf^(0) = +117.0 KJ mol^(-1), C + O_(2) rarr CO_(2), DeltaHf^(0)= -393.0 KJ mol^(-1) S + O_(2) rarr SO_(2), DeltaHf^(0) = -297.0 KJ mol^(-1) . The heat of combustion of CS_(2) + 3O_(2) rarr CO_(2) + 2SO_(2) is

Given C+ 2S rarr CS_(2), DeltaHf^(0) = +117.0 KJ mol^(-1), C + O_(2) rarr CO_(2), DeltaHf^(0)= -393.0 KJ mol^(-1) S + O_(2) rarr SO_(2), DeltaHf^(0) = -297.0 KJ mol^(-1) . The heat of combustion of CS_(2) + 3O_(2) rarr CO_(2) + 2SO_(2) is

C+O_(2) rarr CO_(2), Delta H =-396 kJ mol^(-1) . Heat liberated in formation of 0.154 kg of CO_(2) is

Given that C + O_(2) rarr CO_(2) Delta H^(theta) = -x kJ 2CO + O_(2) rarr 2CO_(2) Delta H^(theta) = - y kJ The enthalpy of formation of CO is :

{:(Given :,C+2StoCS_(2),DeltaH=117 kJ),(,C+O_(2)toCO_(2),DeltaH=-393 kJ),(,S+O_(2)toSO_(2), DeltaH=-297 kJ):} The heat is combustion of CS_(2) to form CO_(2) and SO_(2) is

From the data at 25^(@)C : Fe_(2)O_(3)(s) +3C_(("graphite")) rarr 2Fe(s) + 3CO(g), DeltaH^(Theta) = 492.0 kJ mol^(-1) FeO(s) +C_(("graphite")) rarr Fe(s) CO(g), DeltaH^(Theta) = 155.0 kJ mol^(-1) C_(("graphite")) +O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 393.0 kJ mol^(-1) CO(g)+(1)/(2)O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 282.0 kJ mol^(-1) Calculate the standard heat of formation of FeO(s) and Fe_(2)O_(3)(s) .

From the data at 25^(@)C : Fe_(2)O_(3)(s) +3C_(("graphite")) rarr 2Fe(s) + 3CO(g), DeltaH^(Theta) = 492.0 kJ mol^(-1) FeO(s) +C_(("graphite")) rarr Fe(s) CO(g), DeltaH^(Theta) = 155.0 kJ mol^(-1) C_(("graphite")) +O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 393.0 kJ mol^(-1) CO(g)+(1)/(2)O_(2)(g) rarr CO_(2)(g), DeltaH^(Theta) =- 282.0 kJ mol^(-1) Calculate the standard heat of formation of FeSO(s) and Fe_(2)O_(3)(s) .