The bond dissociation energies of`X_(2),Y_(2)andXY` are in the ratio of`1:0.5:1.DeltaH` for the formation of `XY`is `-200kJmol^(-1)`.The bond dissociation energy of `X_(2)`will be

The bond dissociation energies of X_(2),Y_(2) and XY are in the ratio of 1:0.5:1. DeltaH for the formation of XY is -200 kJ*mol^(-1) . The bond dissociationn energy of X_(2) will be-

The bond dissociation energies of X_2, Y_2 and XY are in the ratio of 1 : 0.5 : 1. DeltaH for the formation of XY is -200 kJ mol^(-1) . The bond dissociation energy of X_2 will be

The bond dissociation energies of X_(2) , Y_(2) and XY are in the ratio of 1 : 0.5 : 1 . Delta H for the formation of XY is -200 kJ * mol^(-1) . The bond dissociation energy of X_(2) is -

If the bond dissociation energies of XY , X_(2) and Y_(2) are in the ratio of 1:1:0.5 and DeltaH_(f) for the formation of Xy is -200 KJ//mol . The bond dissociation energy of X_(2) will be :-