The equilibrium constant (K) for the reaction
`Cu(s)+2Ag^(+) (aq) rarr Cu^(2+) (aq)+2Ag(s)`, will be
[Given, `E_(cell)^(@)=0.46 V`]

The equilibrium constant for the reaction Cu_(s) + 2Ag^+ _ (aq) rarr Cu^2+ _ (aq) +2Ag at 298 k is Given E^@cell=0.46v

Calculate the equilibrium constant of the following reaction aty 298K. Cu(s)+2Ag^+(aq) rarr Cu^(2+)(aq)2Ag(s)~ Given E_(cell)^Theta=0.46V

The equilbrium constant for the reaction : Cu + 2 Ag^(+) (aq) rarr Cu(2+) (aq) +2 Ag, E^@ = 0. 46 V at 299 K is

The equilibrium constant of the reaction; Cu(s)+2Ag + (aq)⟶Cu 2+ (aq)+2Ag(s) E o =0.46V at 298K

Calculate the equilibrium constant of the reaction: Cu(s) + 2Ag^+(aq) → Cu^(2+) (aq) + 2Ag(s) E^o(cell) = 0.46 V

Calculate the equilibrium constant of the reaction : Cu(s)+2Ag^(+)(aq)rarr Cu^(2+)(aq)+2Ag(s): E_("cell")^(@)=0.46V

Calculate equilibrium constant for the reaction at 25^(@)C Cu(s)+2Ag^(+)(aq) hArr Cu^(2+)(aq)+2Ag(s) E^(@) value of the cell is 0.46 " V " .