Let `a_(1),a_(2),a_(3),….,a_(4001)` is an `A.P.` such that `(1)/(a_(1)a_(2))+(1)/(a_(2)a_(3))+...+(1)/(a_(4000)a_(4001))=10`
`a_(2)+a_(400)=50`.
Then `|a_(1)-a_(4001)|` is equal to

Let a_(1),a_(2),a_(3),….,a_(4001) is an A.P. such that (1)/(a_(1)a_(2))+(1)/(a_(2)a_(3))+...+(1)/(a_(4000)a_(4001))=10 a_(2)+a_(4000)=50 . Then |a_(1)-a_(4001)| is equal to

Let a_(1),a_(2),a_(3),….,a_(4001) is an A.P. such that (1)/(a_(1)a_(2))+(1)/(a_(2)a_(3))+...+(1)/(a_(4000)a_(4001))=10 a_(2)+a_(4000)=50 . Then |a_(1)-a_(4001)| is equal to

Let a_(1), a_(2),a_(3), cdots , a_(4001) are in A.P. such that (1)/(a_(1)a_(2))+(1)/(a_(2)a_(3))+ cdots + (1)/(a_(4000) a_(4001))= 10 and a_(2)+ a_(4000) = 50 then find the value of |a_(1)-a_(4001)| .

If a_(1), a_(2), a_(3),…, a_(n) be in A.P. Show that, (1)/(a_(1)a_(2)) + (1)/(a_(2)a_(3)) +….+(1)/(a_(n-1)a_(n)) = (n-1)/(a_(1)a_(n))

If a_(1),a_(2),a_(3),dots,a_(n+1) are in A.P.then (1)/(a_(1)a_(2))+(1)/(a_(2)a_(3))...+(1)/(a_(n)a_(n+1)) is

Let a_(1),a_(2),a_(3),...a_(n) be an AP.Prove that: (1)/(a_(1)a_(n))+(1)/(a_(2)a_(n-1))+(1)/(a_(3)a_(n-2))+......+(1)/(a_(n)a_(1))=

a_(1),a_(2),a_(3)...,a_(n) are in A.P.such that a_(1)+a_(3)+a_(5)=-12 and a_(1)a_(2)a_(3)=8 then:

If a_(1),a_(2),a_(3),....,a_(4001) are terms of AP such that sum_(i=1)^(4000)(1)/(a_(i)a_(i+1))=108a_(2)+a_(4000)=50 then |a_(1)-a_(4000)|=