Find the equation of the ellipse in the following case: eccentricity `e=2/3` and length of latus rectum `=5` .

Find the equation of the ellipse in each of the following cases:vertices at (+-5,0) and length of latus rectum is 8/5.

Taking major and minor axes as x and y - axes respectively , find the equation of the ellipse whose eccentricity is (1)/(sqrt(2)) and length of latus rectum 3 .

Obtain equation of ellipse satisfying given conditions Eccentricity e = (2)/(3) , length of the latus rectum = 5

Find the equation of an ellipse whose latus rectum is 8 and eccentricity is 1/3

…….is the equation of ellipse with eccentricity e = (2)/(3) . Length of latus rectum is 5 and centre of origin.

Find the eccentricity of the ellipse if : the distance between the foci is equal to the length of latus-rectum.

The given equation of the ellipse is (x^(2))/(81) + (y^(2))/(16) =1 . Find the length of the major and minor axes. Eccentricity and length of the latus rectum.

The given equation of the ellipse is (x^(2))/(81) + (y^(2))/(16) =1 . Find the length of the major and minor axes. Eccentricity and length of the latus rectum.

Find the coordinats of the foci, the vertice ,eccentricity and length of latus rectum of ellipse (x^(2))/(25) + (y^(2))/(100) = 1 .