`3x+4=22`

Solve: 2x-7y=7 , 3x+y=22

Find the equation of the circle circumscribing the rectangle whose sides are : x-3y=4, 3x+y=22, x-3y=14, 3x+y=62

The solutioni of x+y+z=7,x+2y+3z=16,x+3y+4z=22 is

Solve 5x-8 = 3x +22

Solve for x: 5x -8 = 3x + 22

If 5x - 8 = 3x + 22 , then find the value of x

If 3x + 2y = 11 & kx + 4y = 22 are coincide lines find value of k.

Solve the inequation: 3x - 22 lt 2, x in N