Reaction between acetone and methyl magnesium chloride followed by hydrolysis will give:

Options

A. Isopropyl alcohol
B. sec. butyl alcohol
C. Tert. butyl alcohol
D. Isobutyl alcohol

Answer

To solve the problem of what the reaction between acetone and methyl magnesium chloride followed by hydrolysis will yield, we can break it down into several steps:

### Step 1: Identify the Reactants
- **Acetone**: The chemical structure of acetone is \( CH_3COCH_3 \).
- **Methyl Magnesium Chloride**: This is a Grignard reagent, represented as \( CH_3MgCl \).

### Step 2: Understand the Reaction Mechanism
- The Grignard reagent \( CH_3MgCl \) acts as a nucleophile. The methyl group (\( CH_3^- \)) has a negative charge and will attack the electrophilic carbon in the carbonyl group of acetone.

### Step 3: Nucleophilic Attack
- In acetone, the carbon atom of the carbonyl group (\( C=O \)) is partially positive due to the electronegativity of oxygen. The nucleophile (\( CH_3^- \)) will attack this carbon atom.
- The reaction can be represented as follows:
\[ CH_3COCH_3 + CH_3MgCl \rightarrow CH_3C(OH)(CH_3)MgCl \]
- This results in the formation of a magnesium alkoxide intermediate.

### Step 4: Hydrolysis
- The next step involves hydrolysis, where the intermediate reacts with water. This will convert the alkoxide into an alcohol.
- The reaction can be represented as:
\[ CH_3C(OH)(CH_3)MgCl + H_2O \rightarrow CH_3C(OH)(CH_3) + Mg(OH)Cl \]
- The product formed is \( CH_3C(OH)(CH_3) \), which is a tertiary alcohol.

### Step 5: Identify the Final Product
- The final product is **tert-butyl alcohol** (or **2-butanol**), which is a tertiary alcohol.

### Conclusion
The reaction between acetone and methyl magnesium chloride followed by hydrolysis yields **tert-butyl alcohol**.

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