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Elimination reaction of 2-Bromopentane t...

Elimination reaction of 2-Bromopentane to form pent-2-ene is:
a) `beta`- Ellimination reaction
b) Follows Zaitsev rule
c) Dehydrohalogenation reaction
d) Dehydration reaction

A

a),b),c)

B

a),c),d)

C

b),c),d)

D

a),b),d)

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the elimination reaction of 2-Bromopentane to form Pent-2-ene, we will analyze each option step by step. ### Step 1: Identify the structure of 2-Bromopentane 2-Bromopentane has the following structure: - It is a five-carbon chain (pentane) with a bromine atom attached to the second carbon. - The structure can be represented as: ``` CH3-CHBr-CH2-CH2-CH3 ``` ### Step 2: Understand the elimination reaction In an elimination reaction, a molecule (in this case, 2-bromopentane) loses atoms or groups to form a double bond, resulting in an alkene (pent-2-ene). ### Step 3: Determine the product The product of the elimination reaction of 2-Bromopentane is Pent-2-ene, which has the following structure: - The double bond is between the second and third carbon atoms: ``` CH3-CH=CH-CH2-CH3 ``` ### Step 4: Analyze the options 1. **Beta-Elimination Reaction**: - This is correct. In beta-elimination, the hydrogen atom is removed from the beta carbon (the carbon adjacent to the carbon holding the leaving group, which is bromine in this case). 2. **Follows Zaitsev Rule**: - This is also correct. The Zaitsev rule states that in elimination reactions, the more substituted alkene is favored. In this case, Pent-2-ene is more substituted than the alternative product (Pent-1-ene). 3. **Dehydrohalogenation Reaction**: - This is correct as well. Dehydrohalogenation refers to the elimination of a hydrogen atom and a halogen atom (bromine) to form the alkene. 4. **Dehydration Reaction**: - This is incorrect. Dehydration reactions specifically involve the removal of water (H2O) and are typically associated with alcohols, not halides. ### Conclusion Based on the analysis: - The correct statements regarding the elimination reaction of 2-Bromopentane to form Pent-2-ene are: - a) Beta-Elimination Reaction (Correct) - b) Follows Zaitsev Rule (Correct) - c) Dehydrohalogenation Reaction (Correct) - d) Dehydration Reaction (Incorrect) ### Final Answer The correct options are: a), b), and c).
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Knowledge Check

  • Elimination reaction of 2-bromopentane to form pent-2-ene is (A) beta- Elimination reaction (B) Follows Zaitsev rule (C) Dehydrohalogenation reaction (D) Dehydration reaction

    A
    (A), (B), (C)
    B
    (A), (C), (D)
    C
    (B), (C), (D)
    D
    (A), (B), (D)
  • Which of the following is a beta -elimination reaction ?

    A
    B
    `CHCl_3 + KOH overset(Delta)to C Cl_2`
    C
    D
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    A
    B
    `CHBr_3+Me_3CO^(ᶱ)K^(o+)to:CBr_2`
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