The reciprocals of the terms of given GP forms a GP

Reciprocals of term of GP is ……….

In a G.P the sum of first n terms is S,the product is P and the sum of the reciprocals of the terms is R.Show that P^2=(S/R)^n .

If S be the sum, p the product and R the sum of the reciprocals of n terms of a G.P., then (S/R)^n is equal to

The sum of 2n terms of a series in G.P. is 2R and the sum of the reciprocals of those terms is R , find the continued product of the terms.

In a G.P. the product of the first four terms is 4 and the second term is the reciprocal of the fourth term. The sum of infinite terms of the G.P is

In a G.P.the product of the first four terms is 4 and the second term is the reciprocal of the fourth term.The sum of infinite terms of the G.P is

If S be the sum,p the product and R the sum of the reciprocals of n terms of a G.P.,then ((S)/(R))^(n) is equal to

The product of first three terms of a G.P. is 1000 . If we add 6 to its second term and 7 to its third term, the resulting three terms form an A.P. Find the terms of the G.P.

The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P. Then the sum of the original three terms of the given G.P. is